Answer:
[tex] \tt{}f {}^{ - 1} (x) = 2x - 8 \\ [/tex]
Step-by-step explanation:
[tex] \\ \sf{}y = \frac{1}{2}x + 4 \\ \\ [/tex]
[tex]\\ \sf{}x = \frac{1}{2} y + 4\\ \\[/tex]
[tex] \sf{}x = \frac{1}{2} y + 4 \\ \\\sf{}x - 4 = \frac{1}{2} y \\ \\ \sf{} \frac{x - 4}{ \frac{1}{2} } = y \\ \\ \sf{} \frac{x}{ \frac{1}{2} } - \frac{4}{ \frac{1}{2} } = y \\ \\ \sf{}x \cdot \frac{2}{1} - 4 \cdot \frac{2}{1} = y \\ \\ \sf{}2x - 8 = y \\ \\ \sf{}y = 2x - 8 \\ \\ [/tex]
[tex] \boxed{\sf{} {f}^{ - 1} (x) = 2x - 8} \\ \\ \\ \\ [/tex]
[tex] \tiny \boxed{ \begin{array}{} \frown \frown \\ \smile \end{array}}[/tex]
