Find the value of n in the question: 2/6+1/3-1/2= n​

Sagot :

[tex] \frac{2}{6} + \frac{1}{3 } - \frac{1}{2} = \\ \frac{1}{3} + \frac{1}{3} - \frac{1}{2} \\ \frac{1}{3} + \frac{1}{3} - \frac{1}{2} \\ \frac{1 \times 2}{3 \times 2} + \frac{1 \times 2}{2 \times 3} - \frac{1 \times 2}{2 \times 3} \\ \frac{2}{6} + \frac{2}{6} - \frac{3}{6} \\ \frac{2 + 2 - 3}{6} \\ \frac{1}{6} [/tex]