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Solution po tsaka sagot po sana pa help naman po​

Solution Po Tsaka Sagot Po Sana Pa Help Naman Po class=

Sagot :

JOPAYDELOSREYES08GO

Answer:

ײ-10×+34=0

Step-by-step explanation:

let xi=5+3i x²= 5-3i to

(x-xi) (x-x²=0

so [x(5+3i) (x-5+3i) =0

so x²-5×+3i× -5×+25-15i -3i×+

15i-9i²=0

so the answer isײ-20×+34=0

correct me if I'm wrong..btw hope it's help

GANAN DIN MODULE NG KAPATID KO..

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