Two balls, one with a mass of 2kg and one with mass 4kg are dropped from 30 m above the ground. What is the PE of the 2kg ball right before it starts to fall?
Given: Solution:
m = PE =
h =
Required : Answer: _______________
PE = ?
Equation:
PE = mgh


Sagot :

Answer:

The potential energy is the energy accumulated in an object by its location.

PE = mgh where, m - mass, g - acceleration due to gravity and h - height

Step 1: Determining the potential energy of the object

Given that

Ball one mass, m_1=2\ kgm1=2 kg

Ball two mass, m_2 = 4 kg m2=4kg

Acceleration due to gravity = 9.8 m/s^2 =9.8m/s2

Height h = 30 m

Potential energy of the 4kg ball PE = mgh = m_2ghm2gh

PE = 4 kg * 9.8 m/s^2 * 30 PE=4kg∗9.8m/s2∗30

PE = 1176 PE=1176

Hence, potential energy of the 4kg ball PE = 1176 PE=1176  joules

and

Potential energy of the 2kg ball PE = mgh = m_1ghm1gh

PE=2kg*9.8m/s^2*30PE=2kg∗9.8m/s2∗30

PE = 588 PE=588

Thus, potential energy of the 2kg ball PE = 588 PE=588 joules.

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