ANTONIETTEPASTOLERO8GO
Answered

find two consecutive positive integers such the square of the first decreased by 17 equals 4 times the second.​

Sagot :

MAURSELLEGO

Answer:

7,8

Step-by-step explanation:

Let x be the first number,

x^2 - 17 = 4(x+1)

x^2 -17 = 4x +4

x^2 - 4x - 21 = 0

(x+3)(x-7)=0

x_1 = -3

x_2 = 7

7,8

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