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1) Find two positive integers whose difference is 1 and the difference of their squares is 5.
2) Find the dimensions of a rectangle whose length is 2 cm more than twice its width, and whose area is 84 square centimeters.

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1.) 3&2

Explanation: 3²+2²= 9 -4

9-4= 5

2.) 6 cm

A= lw

2x + 2(x) =84

2x²+2x-84= 0

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2

x²+x-42=0

(x+7) (x-6) =0

x+7= 0 x-6 =0

-7 -7 +6 +6

x= -7 x= 6

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