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water shoots out from a fountain at 40 m/s an angle of 55° above the horizontal.
a. what time of flight?
b. what is its range? ​

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JANINAGAILE06GO

Letter A.

Solution:

Water shoots out from a fountain at 40 m/s at an angle of 55° above the horizontal.

What is its time of flight?

vel= 40m/s

angle =55

V up = 40 sin (55)= 8.2 m/s

v= u +at

t=(v-u)/g

t=(0-8.2)/-9.8

t= 0.84

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