Answer:
Mean = 17.44
Median = 22.5
Mode = 22.5
Explanation:
Ages Frequency CF
28-30 4 20
25-27 2 16
22-24 6 14
19-21 4 8
16-18 1 4
13-15 2 3
10-12 1 1
Mean:
Find the midpoint of all the classes and multiply it by the frequency of the class.
4 * 29 = 116
2 * 26 = 52
6 * 22 = 132
4 * 20 = 80
1 * 17 = 17
2 * 14 = 28
1 * 11 = 11
Then add it all up and divide it by 25 to get the mean value.
116+52+132+80+17+28+11 = 436
436/25 = 17.44
The answer is 17.44
Median:
Find [tex]\frac{N}{2}[/tex] where N is the sum of the frequency.
4+2+6+4+1+2+1 = 20
20/2 = 10
The first class that has a cumulative frequency(CF) that is higher than 10 is the mean class.
The mean class is 22-24 because it has a cumulative frequency of 14 and 14 is higher than 10.
Next, we find the actual median value with the following formula:
[tex]median = l + \frac{\frac{N}{2}-F}{f} * h[/tex]
l = lower limit of the median class
f = frequency of the median class
F = cumulative frequency of the class preceding the median class
N = total number of observations
h = width of the median class
[tex]median = 21.5 + \frac{10-8}{6} * 3[/tex]
[tex]median = 21.5 + \frac{2}{6} * 3[/tex]
[tex]median = 21.5 + 1[/tex]
[tex]median = 22.5[/tex]
The answer is 22.5
Mode:
We have the find the class with the highest frequency, which is called the modal class. This is 22-24.
Next, we solve for the mode value with the following formula:
[tex]mode = L + \frac{fm-f1}{(fm-f1)+(fm-f2)} * h[/tex]
L is the lower boundary of the modal class
fm is the frequency of the modal class
f1 is the frequency of the class before the modal class
f2 is the frequency of the class after the modal class
h is the class interval
[tex]mode = 21.5 + \frac{6-4}{(6-4)+(6-2)} * 3[/tex]
[tex]mode = 21.5 + \frac{2}{(2)+(4)} * 3[/tex]
[tex]mode = 21.5 + \frac{2}{6} * 3[/tex]
[tex]mode = 21.5 + 1[/tex]
[tex]mode = 22.5[/tex]
The answer is 22.5
PS - pa brainliest po hehe
