Question:
the measure of the four exterior angles of a Pentagon are 54,67,72 and 84.what is the measure if the fift exterior angle? A.73 B.79 C.83 D.85
Answer:
Sum of exterior angles of Pentagon = 360°
let
∠5 = measure of the fifth exterior angle
solve for ∠5,
∠1 + ∠2 + ∠3 + ∠4 + ∠5 = 360°
54° + 67° + 72° + 84 + ∠5 = 360°
54° + 67° + 72° + 84 + ∠5 = 360°
277° + ∠5 = 360°
∠5 = 360° - 277°
∠5 = 83°
[tex]\therefore \;\large\boxed{\text{\sf The fifth exterior angle is $\sf 83^\circ$}}[/tex]
* as always, double check my answers for errors or carelessness.
#No to copy paste solution
#No to plagiarism
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