[tex]\LARGE\color{pink}{{{\boxed{\tt{} \: \: ANSWER : \: \: }}}} [/tex]
[tex]1. \: \: 6 = 12[/tex]
[tex]2. \: \: a = 9[/tex]
[tex]3. \: \: c = 17[/tex]
[tex]4. \: \: 6 = 10[/tex]
[tex]\LARGE\color{blue}{{{\boxed{\tt{} \: \: SOLUTION : \: \: }}}} [/tex]
Given : Figures Of Same Triangle
To Find : Missing Measurements
SOLUTION FOR NO 1
[tex] = {Ac}^{2} = {AB}^{2} + {BC}^{2} [/tex]
[tex] = {13}^{2} = {5}^{2} + \: {BC}^{2} [/tex]
[tex]= {b}^{2} = {13}^{2} - {5}^{2} \: \: b = 12[/tex]
SOLUTION FOR NO 2
[tex] = {Hypotenuse}^{2} = {Base}^{2} +{Altitude}^{2} [/tex]
[tex] = {AB}^{2} = {BC}^{2} + {AC}^{2} [/tex]
[tex] = {15}^{2} = {12}^{2} + {AC}^{2} [/tex]
[tex] = AC = \sqrt{15}^{2} - {12}^{2} = 9 \\ \: a = 9[/tex]
SOLUTION FOR NO 3
[tex] = {AD}^{2} = {AB }^{2} + {BD}^{2} [/tex]
[tex] = {c}^{2} = {8}^{2} + {15}^{2} [/tex]
[tex] = c = 17[/tex]
SOLUTION FOR NO 4
[tex] = {Ac}^{2} = {AB }^{2} + {BC}^{2} [/tex]
[tex] = {26}^{2} = {6}^{2} + {24}^{2} [/tex]
[tex] = {b}^{2} = {26}^{2} - {24}^{2} [/tex]
[tex] = \: b = \sqrt{ {26}^{2} } - {24}^{2} = 10[/tex]
pa brainliest plss hoped that I helped you study well keep safe and God bless
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