Answer:
Simple. It is a G.S. with its first term a = 1 and common ratio r = 1/2 and it contains (n) terms . Therefore its sum S(n)
= a(1 - r^(n)/(1 - r)
= 1(1 - (1/2)^(n)/(1 - 1/2)
= 2 (1 - 2^(-n)) etc
4/3
2^2(3^{-1})
= 4(3^{-1})
Use the ruleb^{-n} = \frac{1}{b^n}to solve3^{-1}
4(3^{-1}) = 4(\frac{1}{3^1} )
= \frac{4}{3}
Step-by-step explanation:
ayan lang alam ko eh sana nakatulong
