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a surveyor is 100 meters from a bridge the angle of elevation to the top if the bridge is 35°.find the height of the bridge​

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Answer: 70 m

Solution:

tan35° approx. equal to 0.700

tanθ = opp/adj

tan35° = opp/100

100(tan35°) = opp

100(0.700) = 70

I'm sorry in advance if this is wrong...

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