The gas in an aerosol can, is at a pressure of 3.00 atm at 25°C. Directions on the Can, warn the user not to keep the
Can in a place where the temp. exceed 52°C. What would the gas pressure in the Can be at 52'C?​


Sagot :

Answer:

The pressure is

=

3.27

a

t

m

Explanation:

We apply Gay Lussac's Law

P

1

T

1

=

P

2

T

2

The initial pressure,

P

1

=

3.00

a

t

m

The initial temperature

T

1

=

25

+

273

=

298

K

The final temperature

T

2

=

52

+

273

=

325

K

The final pressure is

P

2

=

T

2

T

1

P

1

=

325

298

3

=

3.27

a

t

m