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Science

Answered

What is the percent yield for this reaction? NH3 + CO2 → CN2OH4 + H2O

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Answer:

The above equation is already balanced. Starting with 6.55 g of ammonia,

6.55 g NH3 (mol/17.04 g) ( mol urea/2 mol NH3) (60.07 g/mol) = 11.5 g urea

% yield = experimental value (100) / theoretical value = 00.00875 g (100) / 11.5 g = 0.0758%

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