Answer:
This is an oxidation-reduction (redox) reaction:
2 Br⁰ + 2 e- → 2 Br-I
(reduction)
2 H⁰ - 2 e- → 2 HI
(oxidation)
Br2 is an oxidizing agent, H2 is a reducing agent
(hope it helps, correct me if im wrong)
