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A U-tube partly filled with mercury and an unknown liquid is poured into it through the other arm. The surface of separation of the liquids is at the 6.35 cm mark, the 0 mark being at the tube's bottom. The free surface of mercury is at 8.46 cm while that of the unknown liquid 28.24 cm. If the density of mercury is 13.6 g/cc, calculate the density of the unknown liquid

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Mass=? volume=230ml, pressure=740 Torr T=293K MM OF Cl2=71 R=8.14

n=pv/RT=740*230/8.14*293

M/MM=nM=MM*n

mass=740*230/8.14*293 *71

it is found on the upper left corner of the element

Explanation:

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