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B. CONSECUTIVE NUMBER PROBLEM.

1) Find three consecutive numbers such that the sum of the first and three times the second
is forty - four less than five times the third.

Representation:

Checking:

Equation

Solution:​

Sagot :

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Answer:

Representation:

Let x be the first number

Let x+1 be the second number

Let x+2 be the third number

Equation:

x+3(x+1)=5(x+2)-44

Solution:

x+3x+3=5x+10-44

4x+3=5x-34

4x-5x= -34-7

-x= -37

x=37

x+1=38

x+2=39

Checking:

37+3(38)=5(39)-44

37+114=195-44

151=151 TRUE

Answer:

The consecutive numbers are 37, 38, and 39.

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