Area of trapezoid
[tex]\large{area \: = \frac{(b1 \: + \: b2)}{2} h}[/tex]
where,
b1 = base1 = 12 meters
b2 = base2 = 20 meters
h = height = 10 meters
solve for area,
[tex]area \: = \frac{(b1 \: + \: b2)}{2} h \\ \\ area \: = \frac{(12 \: + \: 20)}{2} (10) \\ \\ area \: = 160 \: m^{2} [/tex]
So area of the lot is 160 m²
