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B. Evaluating Algebraic Expression.
Let x = -5 , y = 0 and z = 3
1. x² + y²
2. yz ÷ x
3. 5y + 5z – 2
4. 6²– xyz
5. 2( y + z ) – y


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Answer:

  1. 25.
  2. 0
  3. 13
  4. 36
  5. 6

Solution:

1. x² + y²

  • (-5)² + (0)²
  • 25 + 0
  • 25

2. yz ÷ x

  • (0 × 3) ÷ -5
  • 0 ÷ -5
  • 0

3. 5y + 5z - 2

  • 5(0) + 5(3) - 2
  • 0 + 15 - 2
  • 15 - 2
  • 13

4. 6² - xyz

  • 36 - (-5 × 0 × 3)
  • 36 - 0
  • 36

5. 2(y + z) - y

  • 2(0 + 3) - 0
  • 2(3)
  • 6

Step-by-step explanation:

substitute:

  • x to -5;
  • y to 0; and
  • z to 3.

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