Given:
[tex]P_{\text{Ar}} = \text{0.28 atm}[/tex]
[tex]P_{\text{He}} = \text{280 mmHg} × \frac{\text{1 atm}}{\text{760 mmHg}} = \text{0.368 atm}[/tex]
[tex]P_{\text{N}_{2}} = \text{390 torr} × \frac{\text{1 atm}}{\text{760 torr}} = \text{0.513 atm}[/tex]
Required:
[tex]P_{\text{T}}[/tex]
Solution:
[tex]P_{\text{T}} = P_{\text{Ar}} + P_{\text{He}} + P_{\text{N}_{2}}[/tex]
[tex]P_{\text{T}} = \text{0.28 atm} + \text{0.368 atm} + \text{0.513 atm}[/tex]
[tex]\boxed{P_{\text{T}} = \text{1.16 atm}}[/tex]
[tex]\\[/tex]
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