EO = 26 the perimeter of △EHY = 165
SOLUTION:
=> as the graph shown ∠EOT ≅ ∠EHY and ∠E ≅ ∠E
=> ∠EOT ≅ ∠EHY
•EO = ET
EH ET
=> EO = 40
EO + 18 70
=> 70 EO = 40 EO + T 20
•30 EO = 720
•EO = 26
=> the perimeter of△EHY = EO + OH + HY + EY
= 26 + 18 + 51 + 70
= 165
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