An airtight container with a volume of 4.25 x 10^4, an internal pressure of 100 atm and an internal temperature of 15.00 degree Celsius has washed off the deck of the ship and sinks to its depth where the pressure is 185 atm and the temperature is 5 degrees Celsius. What will the volume of the gas inside when the container breaks under the pressure at this depth? (Combined Gas Law)

Sagot :

P1 V1 / T1 = P2 V2 / T2

Given that
P1 = 100 atm
V1 = 4.25 x 10^4 -> 0.000425
T1 = 15 Celuis -> 288 K

P2 = 185 atm
V2 = ?
T1 = 278 K

(0.000425)(100)/288 = (185)(v)/278
v = 0.000222

The volume of gas inside the container is 2.22 x 10^4