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Math

Answered

5. Find the area of a lot whose width is 5x meters and whose length is 9x + 2y meters.
A. 45x2 - 107 B. 45x + 10xy
C. 45x2 + 10xy
D. 4x - 10xy
with Solution

Sagot :

KIRSCHEGO KIRSCHEGO

Answer:

Given :

Length = 9x+2y

Width = 5x

A = LW or WL

Solution:

A = 5x(9x +2y)

A = 45x² + 10xy

Therefore the answer is Letter C

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