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A square paper has a side represented by the polynomial 4q – 5r + 3s inches. What is the area of the square paper? If a portion of the paper with an area of 2q2 – 12qr + 3 qs + 8r2 – 5rs + s2 square inches is to be removed, what will be the remaining area of the paper?
GIVEN:
UNKNOWN:
FORMULA:
CONCLUSION:
SOLUTION:

Sagot :

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Answer:

GIVEN: Side of square (4q - 5r + 3s) & portion of the paper with an area of (2q² – 12qr + 3 qs + 8r² – 5rs + s²) to be removed

UNKNOWN: total area of the paper & remaining area of the paper

FORMULA:

for the area of the paper : multiplication

Area of paper = (4q - 5r + 3s)×(4q - 5r + 3s)

for the remaining area : substraction

16q² + 25r² + 9s² - 40qr + 24qs - 30rs

- 2q² + 8r² + s² - 12qr + 3qs - 5rs

CONCLUSION: the remaining area of the paper is (14q² + 17r² + 8s² - 28qr + 21 qs - 25rs)

SOLUTION:

Area of paper = (4q - 5r + 3s)×(4q - 5r + 3s)

= 16q² + 25r² + 9s² - 40qr + 24qs - 30rs

16q² + 25r² + 9s² - 40qr + 24qs - 30rs

- 2q² + 8r² + s² - 12qr + 3qs - 5rs

14q² + 17r² + 8s² - 28qr + 21 qs - 25rs

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