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what is the equation of the line that passes through (-12,10) and has a slope of -1/2​

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NEIL082182GO

Answer:

(y-y1)= m (x-x1)

( y - 10 ) = (-1/2) ( x - (-12))

( y - 10 ) = (-1/2) ( x + 12 )

( y - 10) = -1/2 x - 6

y - 10 = (- x - 12 ) / 2

2(y-10) = - x - 12

2y - 20 = -x -12

2y = -x -12 +20

2y + x = 8

x + 2y = 8 - general form (eq)

2y= -x + 8

2y/2 = (-x+8)/2

y = - (1/2)x + 4 - slope & y intercept form (eq)

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