how to solve(3x-⁴y-⁵z-²)/(9x²y-⁸z-⁹)​

Sagot :

Answer:

[tex] = \frac{ {y}^{3} }{3 {x}^{6} {z}^{11} } [/tex]

[tex] \frac{3 {x}^{ - 4} {y}^{ - 5} {z}^{ - 2} }{9 {x}^{2} {y}^{ - 8} {z}^{ - 9} } \\ \frac{3}{9} {x}^{ - 4 - (2)} {y}^{ - 5 - ( - 8)} {z}^{ - 2 - ( - 9)} \\ = \frac{1}{3} {x}^{ - 6} {y}^{3} {z}^{ - 11} [/tex]

[tex] = \frac{ {y}^{3} }{3 {x}^{6} {z}^{11} } [/tex]