Pythagorean Theorem
1. c = 10 , a = 8, b = 6
Solution
[tex]b = \sqrt{c ^{2} - {a}^{2} } \\ b = \sqrt{ {10}^{2} - {8}^{2} } \\ b = \sqrt{100 - 64} \\ b = \sqrt{36 } \\ b = 6[/tex]
2. b = 3, c = 5, a = 4
Solution
[tex]a = \sqrt{ {c}^{2} - {b}^{2} } \\ a = \sqrt{ {5}^{2} - {3}^{2} } \\ a = \sqrt{25 - 9} \\ a = \sqrt{16} \\ a = 4[/tex]
3. a = 12, b = 9, c = 15
Solution
[tex]c = \sqrt{ {a}^{2} + {b}^{2} } \\ c = \sqrt{ {12}^{2} + {9}^{2} } \\ c = \sqrt{144 + 81} \\ c = \sqrt{225} \\ c = 15[/tex]
4. c = 13, b = 5, a = 12
Solution
[tex]a = \sqrt{ {c}^{2} - {b}^{2} } \\ a = \sqrt{ {13}^{2} - {5}^{2} } \\ a = \sqrt{169 - 25} \\ a = \sqrt{144 } \\ a = 12[/tex]
5.a = 24, b = 7, c = 25
Solution
[tex]c = \sqrt{ {a}^{2} + {b}^{2} } \\ c = \sqrt{ {24}^{2} + {7}^{2} } \\ c = \sqrt{576 + 49} \\ c = \sqrt{625} \\ c = 25[/tex]
Answer in the Riddle:
LIGHT
I hope it helps ^_^
