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The time required for an elevator to lift a weight varies jointly with the weight and the distance through which it is to be lifted ang inversely with the power of the motor. it takes 30 seconds for a 10-horsepower motor to lift 100 pounds through 50 feet, what size of motor is required to lift 800 pounds in 40 seconds through 40 feet?​

Sagot :

answer:

t=kwd/p

30=k(100)(50)/10

300=5,000k

300/5,000=5,000k/5,000

3/50=k(constant of variation)

40=5/50(800)(40)/p

40p=19,000

p=480

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