Sagot :
Answer:
This is the solution.
Suppose that all of the flags (even same-colored), are distinct. Then there are 10! ways.
Now we count how many times each arrangement is repeated since same-colored flags are considered the same. 4 white flags could be done in 4! ways (if they are distinguishable). Similar for the other colors. Thus # of repetitions is 4!⋅3!⋅2!⋅1!.
Thus we divide 10! by the number of repetitions to get 10!4!⋅3!⋅2!⋅1!=12600.
Step-by-step explanation:
hope it helps
Answer:
2520 ways
Step-by-step explanation:
no. of ways = (10!)/(5!)(2!)(3!) = 2520