Rhombus SAMT with m∠STM = (3x + 11)°
Solution:
m∠STM = (3x + 11)
Since there is only one given equation, which is 3x + 11,
Assuming triangle TSM is an equilateral triangle from triangle STM
m∠STM = (3x + 11)
m∠STM = 3(49/3) + 11
m∠STM = 49 +11
m∠STM = 60°
m∠MTA = m∠STM/2
m∠MTA = 60/2
m∠MTA = 30°
m∠TSA = 60 + 60
m∠TSA = 120°
m∠TSM = m∠TSA /2
m∠TSM = 120/2
m∠TSM = 60°
Answer:
3.) m∠MTA = 30°
4.) m∠TSM = 60°
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