Given:
[tex]P_{1} = \text{205 kPa}[/tex]
[tex]V_{1} = \text{4.0 L}[/tex]
[tex]V_{2} = \text{12.0 L}[/tex]
Unknown:
[tex]P_{2}[/tex]
Solution:
[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
[tex]P_{2} = P_{1} × \frac{V_{1}}{V_{2}}[/tex]
[tex]P_{2} = \text{205 kPa} × \frac{\text{4.0 L}}{\text{12.0 L}}[/tex]
[tex]\boxed{P_{2} = \text{68.3 kPa}}[/tex]
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