which of the ff is the cube of (2x-1)?


Sagot :

SOLUTION

Use the special product particularly in cube of a binomial property

  • (a-b)³ = a³-3a²b+3ab²-b³

Let a = 2x , b = 1

  • (a-b)³ = (2x)³-3(2x)²(1)+3(2x)(1)²-(1)³
  • (a-b)³ = 8x³-3(4x²)(1)+3(2x)(1)-1
  • (a-b)³ = 8x³-12x²+6x-1

ANSWER

  • 8x³-12x²+6x-1

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