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3.55 mol O2 is enclosed in a 1.5 L container. How many additional moles of O2 should be added to the encounter to increase the volume to 3L at the same temperature and pressure? ​

Sagot :

Given:

[tex]n_{1} = \text{3.55 mol}[/tex]

[tex]V_{1} = \text{1.5 L}[/tex]

[tex]V_{2} = \text{3 L}[/tex]

Unknown:

[tex]n_{\text{additional}}[/tex]

Solution:

Step 1: Calculate the final moles.

[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]

[tex]n_{2} = n_{1} × \frac{V_{2}}{V_{1}}[/tex]

[tex]n_{2} = \text{3.55 mol} × \frac{\text{3 L}}{\text{1.5 L}}[/tex]

[tex]n_{2} = \text{7.10 mol}[/tex]

Step 2: Calculate the additional moles.

[tex]n_{\text{additional}} = n_{2} - n_{1}[/tex]

[tex]n_{\text{additional}} = \text{7.10 mol} - \text{3.55 mol}[/tex]

[tex]\boxed{n_{\text{additional}} = \text{3.55 mol}}[/tex]

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