GIVEN:
[tex](x + 11) {}^{2} + (y - 9) {}^{2} = 16[/tex]
SOLUTION:
[tex](x + 11) {}^{2} + (y - 9) {}^{2} = 16[/tex]
CIRCLE EQUATION
[tex](a,b)²+(y-b)²=r²[/tex]
IS THE CIRCLE WITH A RADIUS R, CENTERED AT
[tex](a,b)[/tex]
REWRITE
[tex](x + 11){}^{2} + (y - 9) {}^{2} = 16[/tex]
IN THE FORM OF THE STANDARD CIRCLE EQUATION
[tex](x - ( - 11)) {}^{2} + (y - 9) {}^{2} = 4 {}^{2} [/tex]
THEREFORE THE CIRCLE PROPERTIES ARE:
[tex](a,b)=(-11,9),r=4[/tex]
FINAL ANSWER:
[tex]\large\red{\boxed{Circle (-11,9)}}[/tex]
[tex]\large\blue{\boxed{radius = 4}}[/tex]
(/^_^)/
