Sagot :
• Question:
A boy weighs 50 kg and is running 3 meters per second, what is the kinetic energy?
• Given:
[tex] \tt mass \: (m)= 50 \: kg [/tex]
[tex] \tt velocity\: (v)= 3 \: m/s[/tex]
• Solution:
✓You need to use the formula to find the kinetic energy of the boy.
[tex] \tt KE= \frac{1}{2} mv {}^{2} \\ [/tex]
✓Substitute the given values to the formula and then solve.
[tex] \tt KE= \frac{1}{2} mv {}^{2} \\ [/tex]
[tex] \tt KE= \frac{1}{2} (50kg )(3m/s) {}^{2} [/tex]
[tex] \tt KE= \frac{1}{2}(50kg)(9m {}^{2}/s {}^{2} )[/tex]
[tex] \tt KE= \frac{50 kg \times 9m {}^{2} }{2s {}^{2} } \\ [/tex]
[tex] \tt KE= \frac{450 \: kgm {}^{2} }{2s {}^{2} } \\ [/tex]
[tex] \tt KE=225 \frac{kgm {}^{2} }{s {}^{2} } \\ [/tex]
• Answer:
✓The quantity 225 kgm²/s² is equal to 225 J. Therefore, the kinetic energy of the boy is 225 J.