Answer:
ans. A
Step-by-step explanation:
f(x)=(x-1)(x+2)(x+3)
y=(x-1)(x+2)(x+3)
y=(x²+x-2)(x+3)
y=x³+4x²+x-6
let x=0
y=x³+4²+x-6
y=0+0+0-6
y=-6
therefore the graph pass thru (0,-6) along y-axis
let y=0
y=(x-1)(x+2)(x+3)
0=(x-1)(x+2)(x+3)
x-1=0
x=1 ; (1,0)
x+2=0
x=-2 ; (-2,0)
x+3=0
x= -3 ; (-3,0)
therefore the graph pass thru (-3,0), (-2,0) and (1,0) along x-axis.
the answer A
