find the center and radius of
3x² + 3y² + 30x + 75 = 0

need help​


Sagot :

Answer:

Are you sure about your equation? kindly check it again please

Answer:

center=(-5, -5)

radius=5

Explanation:

[tex]3x^2 + 3y^2 + 30x +30y+ 75 = 0\\\frac{3x^2 + 3y^2 + 30x + 30y+75 = 0}{3} \\x^{2} +y^{2} +10x+10y+25=0\\(x^{2} +10x)+(y^2+10y) =-25\\(x^{2} +10x+25)+(y^{2}+10y+25) =-25+25+25\\(x+5)^{2} +(y+5)^{2} =25\\[/tex]

[tex]center=(-5, -5)\\radius=5[/tex]