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Math

Answered

A plane flying at 80m/s is uniformly accelerated at the rate of 2.0 m/s². What is the distance it will travel during a 10 s interval after acceleration begins?

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Step-by-step explanation:

s=distance travel

v=final velocity

u=initial velocity

a=acceleration

t=time

formula: s=ut+1/2at^2

=(80m/s)(10s)+1/2(2.0m/s^2)(10s)^2

=900meters

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