evaluate n³+ n + 1 when n=-2
a.9 b.8 c.11 d.10


Sagot :

Answer:

the answer is -9.

Step-by-step explanation:

n=2

[tex]n {}^{3 } + n + 1 [/tex]

[tex] { -2}^{3} + ( - 2) + 1[/tex]

[tex] - 8 + ( - 2) + 1[/tex]

[tex] - 10 + 1[/tex]

[tex] - 9[/tex]