y varies directly as the square of x and inversely as z. if y=3 when x=3 and z=12 find the constant of variation k
a. k=1 b.k=2 c.k=3 d.k=4​


Sagot :

Nihao! Zao an..

The answer is D. 4

Solution and explanation:

This is a combined variation.

[tex]y = \frac{k {x}^{2} }{z} [/tex]

[tex]3 = \frac{ { k3}^{2} }{12} [/tex]

[tex] \frac{3}{1} = \frac{k9}{12} [/tex]

(Do the Cross Multiplication) (3 x 12, 1 x k9)

[tex]36 = k9[/tex]

(Cancel)

[tex] \frac{36}{9} = \frac{k9}{9} [/tex]

[tex] \frac{36}{9} = k[/tex]

(Simplify) (36 divided by 9)

4 = k

k = 4.

Therefore, the constant of variation (k) is 4.

~ GongzhuSisi(◕ᴗ◕✿)

Hope it helps. ehehe(≧▽≦)