Answered

A 50 mL sample of Calcium Hydroxide solution were required 19.50 mL of 0.1050 N HCl in a titration. Calculate the amount of Calcium Hydroxide in the 50 mL sample.

Sagot :

Given:

[tex]N_{\text{acid}} = \text{0.1050 N}[/tex]

[tex]V_{\text{acid}} = \text{19.50 mL}[/tex]

[tex]V_{\text{base}} = \text{50.00 mL}[/tex]

Unknown:

[tex]N_{\text{base}}[/tex]

Solution:

[tex]N_{\text{acid}}V_{\text{acid}} = N_{\text{base}}V_{\text{base}}[/tex]

[tex]N_{\text{base}} = N_{\text{acid}} × \frac{V_{\text{acid}}}{V_{\text{base}}}[/tex]

[tex]N_{\text{base}} = \text{0.1050 N} × \frac{\text{19.50 mL}}{\text{50.00 mL}}[/tex]

[tex]\boxed{N_{\text{base}} = \text{0.04095 N}}[/tex]

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