CHARLESSAMPARANGGO
Answered

vertex of y=3x² +1?​

Sagot :

y = (x+3)^2 - 26

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MISSJINDYSUMMERGO

VERTEX

[tex]y=3x^{2} +1[/tex]

Vertex:

[tex]{\gray{\boxed{\gray{\huge{\boxed{\sf{(0,1)}}}}}}}[/tex]

Solution:

[tex]{\tt{y=3x^{2} +1}}\\{\tt{y=3(x+0)^{2}+1}}\\{\tt{a=3}}\\{\tt{h=0}}\\{\tt{k=1}}\\{\boxed{\tt{(0,1)}}}[/tex]

[tex]{\blue{\boxed{ItzyMidzy:))}}}[/tex]

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