Change the equations to general form:
ax2 + bx+c=0
1. (x-2)(x + 4) = 3(x - 1)


Sagot :

Answer:

x² - x - 5 = 0

Step-by-step explanation:

[tex]\sf (x-2)(x+4)=3(x-1)[/tex]

[tex]\implies \sf x(x) + x(4) + (-2)(x)+(-2)(4)=3(x) + 3(-1)[/tex]

[tex]\implies \sf x^2 + 4x - 2x - 8 = 3x - 3[/tex]

[tex]\implies \sf x^2 + 2x - 8 = 3x - 3[/tex]

[tex]\implies \sf (x^2 + 2x - 8) - (3x-3) =3x-3-(3x-3)[/tex]

[tex]\implies \sf x^2 + 2x - 8 - 3x + 3 = 0[/tex]

[tex]\implies \sf x^2 + 2x - 3x -8 + 3 = 0[/tex]

[tex]\implies \boxed{\boxed{\sf x^2 - x - 5 = 0}}[/tex]

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