how many meters of cloth not used in 3/5 -1/8= ​

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SUBTRACTION

SUBTRACTING DISSIMILAR FRACTIONS

Question:

How many meters of cloth not used from 3/5 meters subtracted to 1/8 m?

Step-by-step explanation:

Step 1: Change the dissimilar fractions into similar fractions by finding the least common denominator.

The denominators are 5 and 8. Given those denominators, we will using the listing method.

Multiple of 5 and 8:

[tex]5=\{5, 10, 15, 20, 25, 30, 35, \boxed{40}, 45, 50...\} \\8=\{8, 16, 24, 32, \boxed{40}, 48, 56, 64, 72, 80...\}[/tex]

The least common multiple (LCM) of 5 and 8 is 40. Therefore, 40 is the LCD.

Step 2: Divide the LCD by the two denominator and multiply to their numerator itself. Then, subtract the second product from the first product to find the numerator.

The LCD is 40. For first fraction...

divide it by 5 and multiply to the numerator 3.

Eq₁ & its solution: 40 ÷ 5 × 3 = 24.

[tex]N = 40 \div 5 \times 3\\N = 8 \times 3\\\boxed{N = \bold{24}}[/tex]

The first value is 24.

For second fraction...

divide it by 8 and multiply to the numerator 1.

Eq₂ & its solution: 40 ÷ 8 × 1 = 5

[tex]N = 40 \div 8 \times 1\\N = 5 \times 1\\\boxed{N = \bold{5}}[/tex]

The second value is 5.

The values are 24 and 5.

Then we need to 'subtract 5 from 24'.

Twenty-four minus five is equal to nineteen.

Hence, 19 would be the denominator. Therefore, 19/40 is the difference.

Step 3: Reduce the fraction if possible.

Since 19/40 is simplified, it would not have to reduce.

Solution:

[tex]\dfrac{3}{5}-\dfrac{1}{8} = \dfrac{24-5}{40} = \boxed{\dfrac{19}{40}}[/tex]

Answer:

[tex]\dfrac{19}{40} m[/tex] or nineteen-fortieth / nineteen over forty meter

Related link:

https://brainly.ph/question/10078201

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