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Suppose w varies directly as x and inversely as the square of y. When x = 8 when y = 4 and w = 18, what is the value of w if x = 4 and y = 6?​

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Answer:

Suppose w varies directly as x and inversely as the square of y. When x = 8 when y = 4 and w = 18, what is the value of w if x = 4 and y = 6?

w=kx/y^2

18=k(8)

(4)^2

k(8)= 18(16)

k(8)=288

k=288/8

k=36

w=(36)(4)

(6)^2

w= 144

36

w=4

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