if y varies inversely as x and y = 48 when x = 10, find y when x = 32​

Sagot :

Answer:

[tex]y = \frac{k}{x } \\ 48 = \frac{k}{10} \\ 480 = k \\ y = \frac{480}{x} \\ y = \frac{480}{32} \\ y = 15[/tex]