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IV - Solve each problem. Indicate your solution below..
1. The values of three quantities A, B, and C, are 2x2 + 3x - 5, -8x2 + 42, and 18x2 - 4x - 9,
respectively. Give the total value of the three quantities.
nally
ber
2. If 5a- 9a + 7 is subtracted from 14a2 + 2a + 16, what is the difference?

3. From the sum of 6b3 - 3b2 + 17b-9 and 9b3 + 13b2 - 8b-16, subtract 2263 +3162 - 18b +
25.
4. The lengths of three logs are 3x + 5 meters, 4x - 1 meters, and 2x + 9 meters. Find the
sum of their lengths.
5. What should be added to 27x2 - 32x + 40 to obtain 56x2 + 19x + 72?​

Sagot :

MINYOONAH623GO

Answer:

1. 12x^2-x+28

2. 9a^2+11a+9

3. 2248b^3+3152b^2-27b+50

4. 9x+13

5. 29x^2+51x+32

Step-by-step explanation:

1. (2x^2 + 3x - 5)+ (-8x^2 + 42) +(18x^2 - 4x - 9)= 12x^2-x+28

2. (14a^2 + 2a + 16)-(5a^2- 9a + 7) = 9a^2+11a+9

3. (6b^3 - 3b^2 + 17b-9) +( 9b^3 + 13b^2 - 8b-16) = 15b^3 +10b^2 +9b−25

   (2263b^3 +3162b^2 - 18b + 25) - (15b^3 +10b^2 +9b−25) =

   =2248b^3+3152b^2-27b+50

4. (3x + 5) +(4x - 1)+ ( 2x + 9)= 9x+13

5. (56x^2 + 19x + 72) - (27x^2 - 32x + 40)= 29x^2+51x+32

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