Solution:
Step 1: Calculate the molar mass of CaCO₃.
molar mass = (40 g/mol × 1) + (12 g/mol × 1) + (16 g/mol × 3)
molar mass = 100 g/mol
Step 2: Calculate the percentage composition of CaCO₃.
For %Ca
[tex]\text{\%Ca} = \frac{\text{40 g/mol × 1}}{\text{100 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%Ca = 40\%}}[/tex]
For %C
[tex]\text{\%C} = \frac{\text{12 g/mol × 1}}{\text{100 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%C = 12\%}}[/tex]
For %O
[tex]\text{\%O} = \frac{\text{16 g/mol × 3}}{\text{100 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%O = 48\%}}[/tex]
Answers:
1) b.
2) a.
3) c.
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