What volume of fluorine gas is need to prepare 50.0 ml of chlorine gas at same conditions of temperature and pressure?

The reaction is 2KCl(aq) + F2(g) 2KF(aq) + Cl2(g)



Sagot :

The volume of Fluorine gas : 50 ml

Further explanation  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.  

Avogadro's hypothesis states that:  

In the same temperature and pressure, in the same volume conditions, the gas contains the same number of molecules  

So it applies: the ratio of gas volume will be equal to the ratio of gas moles  

Given  

50 ml Cl₂

Required

The volume of fluorine gas

Solution  

Reaction

2KCl(aq) + F₂(g) ⇒2KF(aq) +Cl₂(g)

We use the Avogadro formula

[tex]\tt \dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}[/tex]

1 = Cl₂, 2 = F₂

mol ratio Cl₂ : F₂ from the equation : 1 : 1, so :

50/1 = V₂/1

V₂ = 50 ml of fluorine gas

   

Learn more  

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