AREA
Question: What is the area of the rectangle whose length is (x+3) and width (x-2)
Formula (Rectangle): [tex]A=(L)(W)[/tex]
Representations:
[tex](x+3)\:Length[/tex]
[tex](x-2)\:Width[/tex]
Equation:
[tex]A=(x+3)(x-2)[/tex]
Solution:
[tex](x+3)(x-2)[/tex]
[tex]x(x)+x(-2)+3x+3(-2)[/tex]
[tex]x^{2} -2x+3x-6[/tex]
[tex]x^{2} +x-6[/tex]
Answer:
The area of a rectangle is
[tex]{\red{\huge{\boxed{x^{2} +x-6}}}}[/tex]
[tex]{\purple{\boxed{Soyeon:))}}}[/tex]
